30.0 ~mL of the given HCl solution requires 20.0 ~mL of 0.1 M sodium carbonate solution for complete neutralisation. What is the volume of this HCl solution required to neutralise 30.0 ~mL of 0.2 M NaOH solution?

Step-by-step solution

Given, Volume of HCl solution (V₁ )=30 ~mL Volume of sodium carbonate solution ( Na ₂ CO ₃ ) (V₂ )=20 ~mL Concentration of Na ₂ CO ₃ solution (M₂ )=0.1 M Volume of NaOH solution (V₃ )=30.0 ~mL Concentration of NaOH solution (M₃ )=0.2 M M₁ V₁=M₂ V₂ where, M₁ is concentration of HCl solution. M₁= M₂ V₂ V₁ = 0.1 20 30 =0.066 M Also, HCl solution required to neutralise 30 ~mL of 0.2 NaOH is calculated as follows : M₁ V_f=M₃ V₃ (where, V_f is the volume of HCl solution required) V_f= M₃ V₃ M₁ = 0.2 30 0.066 =90 ~mL Henc