Chlorine oxidises sulphur dioxide in the presence of water to give an oxyacid A . Chlorine also oxidises iodine in the presence of water to give an oxyacid B . The oxidation states of S and I in A and B are respectively

Step-by-step solution

(i) When chlorine oxidises sulphur dioxide in presence of water, it gives H ₂ SO ₄ as oxyacid (A) . The reaction occurs as follows : Cl ₂+ SO ₂+2 H ₂ O H ₂ SO ₄+2 HCl The oxidation number of sulphur in H ₂ SO ₄ is 2+x+(4 x-2)=0 or, where x= oxidation state of sulphur (S). x+2-8=0 x=+6 Hence, oxidation state of (S) in H ₂ SO ₄ is (+) 6. (ii) When chlorine ( Cl ₂ ) oxidises iodine ( I ₂ ) in presence of water, it gives HIO ₃ as oxyacid (B) , the reaction occurs as follows: 5 Cl ₂+ I ₂+6 H ₂ O 2 HIO ₃+10 HCl . The oxi