AP EAMCET201920 Apr 2019Evening ShiftChemistryRedox ReactionsActual
Disproportionation products of one mole of MnO ₄⁻² in aqueous acidic medium are
Options
- A1 3 ~mol ^ a MnO ₄⁻, 2 3 ~mol of MnO ₂
- B2 3 ~mol ^2 MnO ₄⁻, 1 3 ~mol of MnO ₂
- C1 3 ~mol _ of Mn ₂ O ₇, 1 3 ~mol of MnO ₂
- D2 3 ~mol of Mn ₂ O ₇, 1 3 ~mol of MnO ₂
Correct answer
B. 2 3 ~mol ^2 MnO ₄⁻, 1 3 ~mol of MnO ₂
Step-by-step solution
2 e⁻+4 H ⁺+ MnO ₄²⁻ MnO ₂+2 H ₂ O ( MnO ₄²⁻ MnO ₄⁻+e⁻ ) 2 Overall reaction, 3 MnO ₄²⁻+4 H ⁺ MnO ₂+2 MnO ₄⁻+2 H ₂ O 3 ~mol MnO ₄²⁻ gives 1 ~mol MnO ₂ 1 ~mol MnO ₄²⁻ 1 3 ~mol of MnO ₂ Moreover, 3 ~mol of MnO ₄²⁻ gives 2 ~mol MnO ₄⁻ 1 ~mol MnO ₄²⁻ 2 3 ~mol MnO ₄⁻ Hence, option (b) is correct.