The volume of (0.02 M ) acidified permanganate solution required for complete reaction of (60 ~mL ), of (0.01 M I ⁻ )ion solution to form ( I ₂ ) in ( mL ) is

Step-by-step solution

Reaction of ( KMnO ₄ ) with ( I ⁻ )converting ( I ₂ ) is (2 KMnO ₄+10 I ⁻ 5 I ₂+2 Mn ⁺² ) (n )-factor of ( KMnO ₄=5 ) (in acidic medium) ( I ⁻ )convert into ( I ₂ ) then, (n )-factor (=2 ) Number of equivalent of ( KMnO ₄ ) (= ) Number of equivalent of ( I ) ( aligned 0.02 V 5 & =60 0.01 2 V & =6 ~mL aligned )