AP EAMCET201823 Apr 2018Morning ShiftChemistryRedox ReactionsActual
From the given reaction 2 KMnO ₄ +3 H ₂ SO ₄+5 H ₂ O ₂ K ₂ SO ₄+2 MnSO ₄ +8 H ₂ O +5 O ₂ Find the normality of H ₂ O ₂ solution, if 20 ~mL of it is required to react completely with 16 mL of 0.02 M KMnO ₄ solution. ( . Molar mass of KMnO ₄=158 ~g ~mol ⁻¹ )
Options
- A4 10⁻² ~N
- B2 10⁻² ~N
- C6 10⁻² ~N
- D8 10⁻² ~N
Correct answer
D. 8 10⁻² ~N
Step-by-step solution
Using law of equivalence Number of gram equivalence of H ₂ O ₂= number of gram equivalence of KMnO ₄ Number of gram equivalence = normality volume ( in litres) or normality = molarity valence factor for KMnO ₄ is 5 in this reaction. Since, equivalences are equal, considering volume in mL . So, aligned N & 20=0.02 5 16 N & = 0.02 5 16 20 = 0.01 5 16 10 & =0.001 5 16 & =0.001 80=8 10⁻² ~N aligned