KCET2014MathematicsMathematical Reasoning
If ( a, b ) and ( c ) are in A.P., then the value of ( | array lll x+2 & x+3 & x+a x+4 & x+5 & x+b x+6 & x+7 & x+c array | ) is
Options
- A( x-(a+b+c) )
- B( 9 x²+a+b+c )
- C( 00 )
- D( a+b+c )
Correct answer
C. ( 00 )
Step-by-step solution
Given ( | array ccc x+2 & x+3 & x+a x+4 & x+5 & x+b x+6 & x+7 & x+6 array | ) ( R₁ R₁-R₂ ; R₂ R₂-R₃ ) ( = | array ccc -2 & -2 & a-b -2 & -2 & b-c x+6 & x+7 & x+c array | ) Since, a, b, c are in A.P. then ( a-b=b-c ) So, ( R₁ R₂ ) Therefore, ( =0 )