Which of the following is a subgroup of the group G= 2^ n n Z under multiplication?

Step-by-step solution

Since, 4^ n n N , 3^ n n Z and 6^ n n N are not subset of the group G = 2^ n n Z and not satisfy all the properties of group axiom but 4^ n n Z is a subset of G = 2^ n n Z and satisfy all the properties, i.e., closure, associative, multiplicative inverse, multiplicative identity exist with respect to multiplication. So, 4^ n n Z is a subgroup.