One mole of N ₂ H ₄ loses 10 moles of electrons to form a new compound Z . Assuming that all the nitrogens appear in the new compound, what is the oxidation state of nitrogen in Z ? (There is no change in the oxidation state of hydrogen.)

Step-by-step solution

N ₂ H ₄-10 e⁻ X¹⁰⁺ (with two N atoms) Total oxidation number of two N atoms in N ₂ H ₄ , aligned 2 x+4 & =0 2 x & =-4 aligned N ₂ H ₄ loses 10 electrons, so total oxidation number of two N -atoms increases by 10 , i.e., the total oxidation number of two N -atoms in Y=-4+10=+6 Oxidation number of each N atom in X¹⁰⁺=+3