Two particles of masses ( m₁ ) and ( m₂ ) have equal kinetic energies. The ratio of their momentum is

Step-by-step solution

Given, kinetic energy of two particles of masses ( m₁ ) and ( m₂ ) is equal, that is, [ 1 2 m₁ v₁²= 1 2 m₂ v₂² ] We know momentum ( =p=m v ) [ array l 1 2 m₁ ² v₁ ² m₁ = 1 2 m₂ ² v₂ ² m₂ 1 2 p₁ ² m₁ = 1 2 p₂ ² m₂ p₁ ² p₂ ² = m₁ m₂ p₁ p₂ = m₁ m₂ array ] Therefore, ratio of momenta is ( m₁ : m₂ )