The work-function of a metal is 1 eV . Light of wavelength 3000 Å is incident on this metal surface. The velocity of emitted photoelectrons will be

Step-by-step solution

Given, Work-function, ₀= leV =1.6 10⁻¹⁹ ~J Wavelength, =3000 Å=3000 10⁻¹⁰ ~m As, we know that, E=h v= h c = 6.6 10⁻³⁴ 3 10⁸ 3000 10⁻¹⁰ =6.6 10⁻¹⁹ ~J Also, E= ₀+ KE KE =E- ₀ 1 2 m v²=E- ₀v²= (6.6 10⁻¹⁹-1.6 10⁻¹⁹ ) 2 9.1 10⁻³¹ = 5 10⁻¹⁹ 2 9.1 10⁻³¹ =1.1 10¹²v=1.01 10⁶ 1 10⁶ ~m / s