The number of photons falling per second on a completely darkened plate to produce a force of ( 6.62 10⁻⁵ ~N ) is ' ( n ) '. If the wavelength of the light falling is ( 5 10⁻⁷ ~m ), then ( n= ) ( 10²² ). ( (h=6.62 10⁻³⁴ ) J _ S )

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Correct answer: B. ( 05 )

Given, force, F=6.62 10⁻⁵ ~N ; wavelength, =5 10⁻⁷ ~m Now, C F= h c n t or F= h n t n t = F h = 6.62 10⁻⁵ 6.62 10⁻³⁴ 5 10⁻⁷=5 10²² Therefore, number of photons falling per second =5 10²²

The number of photons falling per second on a completely darkened plate to produce a force of ( 6.62 10⁻⁵ ~N ) is ' ( n ) '. If the wavelength of the light falling is ( 5 10⁻⁷ ~m ), then ( n= ) ( 10²² ). ( (h=6.62 10⁻³⁴ ) J _ S )

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