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KCET2018PhysicsDual Nature of Matter

A proton and an ( ) particle are accelerated through the same potential difference ( V ). The ratio of their de-Broglie's wavelength is

Options

  1. A( 2 )
  2. B( 2 2 )
  3. C( 3 )
  4. D( 2 3 )

Correct answer

B. ( 2 2 )

Step-by-step solution

The de Broglie wavelength is defined as [ = h 2 m q V ] Now, for proton ( _ p = h 2 m_ p q V ) For ( - ) particle, ( _ = h 2 m_ a q_ a V ) Since [ m_ p =4 m, q_ p =e ; m_ =4 m, q_ =2 e ] Ratio of their de Broglie wavelengths is [ _ p _ a = m_ a q_ a m_ p q_ p = 4 m 2 e m e = 8 =2 2 ]

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