A linear object of height ( 10 ~cm ) is kept in front of a concave mirror of radius of curvature ( 15 ~cm ), at a distance of ( 10 ~cm ). The image formed is

Step-by-step solution

Given, height of object ( =10 ~cm ); radius of curvature ( =15 ~cm ); distance of object ( =10 ~cm ). Since radius of curvature is ( 15 ~cm ), so focal length ( = 15 2 =7.5 ~cm ) ( f Thus, the object is placed between centre of curvature and focus of the concave mirror. Therefore, the image formed is magnified and inverted.