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KCET2016PhysicsDual Nature of Matter

Total energy of electron in an excited state of hydrogen atom is ( -3.4 eV ). The kinetic and potential energy of electron in this state

Options

  1. A( K =-3.4 eV U=-6.8 eV )
  2. B( K =3.4 eV U =-6.8 eV )
  3. C( K =-6.8 eV U=+3.4 eV )
  4. D( K =+10.2 eV U =-13.6 eV )

Correct answer

B. ( K =3.4 eV U =-6.8 eV )

Step-by-step solution

Given, total energy of electron =-3.4 eV Now, total energy |=| kinetic energy Therefore, kinetic energy of electron in this excited state is 3.4 eV Potential energy of electron =2 Total energy =2 (-3.4 eV )=-6.8 eV ( Total energy = Kinetic energy + Potential energy 2 Total energy = Potential energy ) Therefore, kinetic energy and potential energy of electron in this state is 3.4 eV and -6.8 eV , respectively

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