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KCET2014PhysicsDual Nature of Matter

A microscope is having objective of focal length ( 1 ~cm ) and eyepiece of focal length ( 6 ~cm ). If tube length is ( 30 ~cm ) and image is formed at the least distance of distinct vision, what is the magnification produced by the microscope ? Take D ( =25 ~cm ).

Options

  1. A( 06 )
  2. B( 150 )
  3. C15
  4. D( 125 )

Correct answer

B. ( 150 )

Step-by-step solution

Given, focal length of objective, ( f_ o =1 ~cm ); focal length of eyepiece, ( f_ e =6 ~cm ); length of tube, ( L=30 ) Using ( M= L f₀ (1+ D f_ e )= 30 1 (1+ 25 6 )=30(1+4.166) ) ( M=155=150 ) Therefore, magnification produced by the microscope is, approximately, ( 150 ).

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