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KCET2014PhysicsDual Nature of Matter

A fringe width of a certain interference pattern is ( =0.002 ~cm ). What is the distance of ( 5^ th ) dark fringe from center?

Options

  1. A( 1 10⁻² ~cm )
  2. B( 11 10⁻² ~cm )
  3. C( 1.1 10⁻² ~cm )
  4. DNone of the above

Correct answer

D. None of the above

Step-by-step solution

Given, fringe width ( =0.002 ~cm ); distance of ( n^ th ) fringe is given as ( x_ n =(2 n+1) D 2 d ) We know fringe width is ( = D 2 ) For ( 5 ) th dark fringe, ( n=4 ) ( _ n =(2 4+1) 0.002 2 =9 0.001=0.009 ~cm )

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