The additional energy that should be given to an electron to reduce its de-Broglie wavelength from 1 ~nm to 0.5 ~nm is

Step-by-step solution

The de-Broglie wavelength, = h 2 m E_ k 1 E_ k ( h and m remains constant) Here, in given condition array ll ₁ ₂ = E_ k₂ E_ k₁ , ₁ ₂ = 4 E E ₁=2 ₂, & ₂= ₁ 2 array So, if E_ k is increased by four times, then becomes half. Additional kinetic energy that should be supplied to the electron =4 E_ k -E_ k =3 E_ k