KCET2010PhysicsDual Nature of Matter
The de-Broglie wavelength of the electron in the ground state of the hydrogen atom is ..... (radius of the first orbit of hydrogen atom =0.53 Å ).
Options
- A1.67 ~A
- B3.33 Å
- C1.06 Å
- D0.53 Å
Correct answer
B. 3.33 Å
Step-by-step solution
According to Bohr's quantisation of angular momentum m v r= n h 2 or h mv = 2 r n ...(i) de- Broglie wavelength = h mv ...(ii) From Eqs. (i) and (ii), we get Wavelength = 2 r n aligned &= 2 0.53 Å 1 &=3.33 Å aligned