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AIIMS 2017
Exam
AIIMS
Year
2017
Subject
Chemistry
Chapter
Chemical Kinetics

AIIMS 2017 · Chemistry · Chemical Kinetics

The chemical reaction, 2 O_3 3 O_2 proceeds as follows : Step 1:...

The chemical reaction, 2O3⟶3O22 \mathrm{O}_3 \longrightarrow 3 \mathrm{O}_2 proceeds as follows : Step 1: O3⇌O2+O\mathrm{O}_3 \rightleftharpoons \mathrm{O}_2+\mathrm{O} .(fast) Step 2:O+O3⟶2O22: \mathrm{O}+\mathrm{O}_3 \longrightarrow 2 \mathrm{O}_2 .(slow) The rate law expression should beThe chemical reaction, 2 O_3 3 O_2 proceeds as follows : Step 1: O_3 leftharpoons O_2+O .(fast) Step 2: O+O_3 2 O_2The chemical reaction, 2 O_3 3 O_2 proceeds as follows : Step 1: O_3 leftharpoons O_2+O .(fast) Step 2: O+O_3 2 O_2

Options

  1. Ar=k′[O3][O2]r=k^{\prime}\left[\mathrm{O}_3\right]\left[\mathrm{O}_2\right]
  2. Br=k′r=k^{\prime}\left[\mathrm{O}_3\right]^2[O2]−1\left[\mathrm{O}_2\right]^{-1}
  3. Cr=k′[O3]2r=k^{\prime}\left[\mathrm{O}_3\right]^2
  4. Dunpredictable.

Correct answer

B. r=k′r=k^{\prime}\left[\mathrm{O}_3\right]^2[O2]−1\left[\mathrm{O}_2\right]^{-1}

Step-by-step solution

As the slowest step is the rate determining step, hence from step 2 , The chemical reaction, 2 O_3 3 O_2 proceeds as follows : Step 1: O_3 leftharpoons O_2+O .(fast) Step 2: O+O_3 2 O_2
From step 1, Keq=[O2][O][O3]K_{e q}=\frac{\left[\mathrm{O}_2\right][\mathrm{O}]}{\left[\mathrm{O}_3\right]}The chemical reaction, 2 O_3 3 O_2 proceeds as follows : Step 1: O_3 leftharpoons O_2+O .(fast) Step 2: O+O_3 2 O_2
From eq. (i) and (ii), r=k K_{e q} \frac{\left[\mathrm{O}_3\right]^2}{\left[\mathrm{O}_2\right]}=k^{\prime}\left[\mathrm{O}_3\right]^2\left[\mathrm{O}_2\right]^{-1} \quad\left[\because k^{\prime}=k K_{e q}\right]
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