Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
KCET2011PhysicsKinetic Theory of Gases

A perfect gas at 27^ C is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be

Options

  1. A600^ C
  2. B327^ C
  3. C54^ C
  4. D300^ C

Correct answer

D. 300^ C

Step-by-step solution

We know for perfect gas Here, V V₂ = T₁ T₂ According to question, V₁=V then V₂=2 V and T₁=300 ~K aligned 1 2 &= 300 T₂ T₂ &=600 ~K T₂ &=327^ C aligned So, t=327-27=300^ C

Practice Kinetic Theory of Gases on Quantrex Academy →

More from Kinetic Theory of Gases

A vessel of volume 27 10^4 cc, contains a mixture of Hydrogen (molar mass = 2 g mol⁻¹ ) and oxygen (molar mass = 32 g mol⁻¹ ) gas at standard temperature and pressure. If the mass 2026Find the mass of oxygen gas with which 1.882 10²³ degrees of freedom are associated at N.T.P. Given: Molar mass of diatomic gas, oxygen is 32 g mol⁻¹ and oxygen molecule possess th 2026An ideal gas has molar specific heat 5R 2 at constant pressure. If 1662 J of heat brings about 50 K temperature change, the number of moles of gas is 2026A jar is filled with two monoatomic non-interacting gases A and B with total masses M_A and M_B , respectively. The molar mass of A is double the molar mass of B . If the jar is ke 2026The graph of pressure P and volume V of 1 mole of an ideal gas at constant temperature is 2026Gas at pressure P, temperature T, and volume V is filled in jar A. Another jar B is filled with gas having parameters 2P , V 4 , 2T . The ratio of number of molecules of jar B to t 2026An ideal gas ( = 1.5 ) is expanded adiabatically. To reduce the root mean square velocity of molecules two times, the gas should be expanded 2026Assuming the expression for the pressure exerted by the gas, it can be shown that pressure is 2026 Full Kinetic Theory of Gases list All KCET PYQs