A body of mass 10 ~kg is kept on a horizontal surface. The coefficient of kinetic friction between the body and the surface is 0.5 . A horizontal force of 60 ~N is applied on the body. The resulting acceleration of the body is about

Step-by-step solution

Given, mass of the body, m=10 ~kg Coefficient of kinetic friction, _k=0.5 Force applied in horizontal direction, F=60 ~N Let f be the frictional force on the body. Thus, m a=F- m g=60-10 (10)(0.9)=60-50 10 a=10 a=1 ~m / s ^2