KCET2018PhysicsLaws of Motion
A block rests on a rough inclined plane making an angle of ( 30^ ) with the horizontal. The coefficient of static friction between the block and the plane is ( 0.8 ). If the frictional force on the block is ( 10 ~N ), the mass of the block is ( ( g =10 ~ms ⁻² ) )
Options
- A( 1 ~kg )
- B( 2 ~kg )
- C( 3 Kg )
- D( 4 Kg )
Correct answer
B. ( 2 ~kg )
Step-by-step solution
Given, coefficient of static friction, ( =0.8 ); frictional force, ( f=10 ~N ) Now, ( f=m g ) [ array l 10=m 10 30^ 10=m 10 1 2 m= 10 5 =2 array ] Therefore, mass of the block is ( 2 ~kg )