KCET2018PhysicsLaws of Motion
A man weighing ( 60 Kg ) is in a lift moving down with an acceleration of ( 1.8 ~ms ^ (-2) ). The force exerted by the floor on him is
Options
- A( 588 ~N )
- B( 480 ~N )
- CZero
- D( 696 ~N )
Correct answer
B. ( 480 ~N )
Step-by-step solution
Given, weight of man =60 ~kg ; acceleration =1.8 ~ms ⁻² Force exerted by floor on man =m(g-a) where g is acceleration due to gravity =9.8 ~ms ⁻² Therefore, force exerted =60(9.8-1.8)=60 8.0=480 ~N Hence, force exerted by floor on man =480 ~N