A car moving with a velocity of ( 20 ~m ~s ⁻¹ ) is stopped in a distance of ( 40 ~m ). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

Step-by-step solution

Given, velocity of car =20 ~ms ⁻¹ ; distance =40 ~m We know, distance travelled = ( velocity )² 2 acceleration acceleration = ( velocity )² distance travelled = (20)² 40 = 400 40 =10 ~ms ⁻² Therefore, acceleration =10 ~ms ⁻² When Velocity =2 20=40 ~ms ⁻¹ then, distance travelled = (40)² 10 = 1600 10 =160 ~m Thus, distance travelled by car =160 ~m