KCET2016PhysicsLaws of Motion
Maximum acceleration of the train in which a ( 50 ~kg ) box lying on its floor will remain stationary (Given : Co-efficient of static friction between the box and the train's floor is ( 0.3 ) and ( g=10 m s⁻² ) )
Options
- A( 5.0 ~ms ⁻² )
- B( 3.0 ~ms ⁻² )
- C( 1.5 ~ms ⁻² )
- D( 15 m s⁻² )
Correct answer
B. ( 3.0 ~ms ⁻² )
Step-by-step solution
Given, mass of box =50 ~kg ; coefficient of static friction =0.3 ; g=10 ~ms ⁻² Train moving along this direction In order that the box remains stationary, we must have m a= N m a= m g a= g=0.3 10=3 Therefore, maximum acceleration of the train =3 ~ms ⁻²