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KCET2009PhysicsLaws of Motion

A body of mass 0.05 ~kg is observed to fall with an acceleration of 9.5 ~ms ⁻² . The opposing force of air on the body is (g=9.8 ~ms ⁻² )

Options

  1. A0.015 ~N
  2. B0.15 ~N
  3. C0.030 ~N
  4. Dzero

Correct answer

A. 0.015 ~N

Step-by-step solution

From, Newton's laws of motion, or aligned mg - F _ air &= ma F _ air &= m ( g - a ) &=0.05(9.8-9.5) &=0.015 ~N aligned

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