KCET2008PhysicsLaws of Motion
A mass of 10 ~kg is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of 60^ with the vertical. The new reading of the balance is
Options
- A20 ~kg - wt
- B10 ~kg -wt
- C10 3 ~kg - wt
- D20 3 ~kg -wt
Correct answer
A. 20 ~kg - wt
Step-by-step solution
The situation is shown in figure At an angle of 60^ , aligned T &= mg T &= mg = 10 g 60^ &= 10 1 / 2 ~kg - wt . &=20 ~kg - wt aligned