A body of mass 4 ~kg is accelerated upon by a constant force, travels a distance of 5 ~m in the first second and a distance of 2 ~m in the third second. The force acting on the body is

Step-by-step solution

Distance travelled by the body in n ^ th second is given by aligned S _ n &= u + a 2 (2 n -1) 5 &= u + a 2 (2 1-1) 5 &= u + a 2 2 &= u + a 2 (2 3-1) 2 &= u + 5 2 a aligned Solving Eqs. (i) and (ii), we get a=- 6 4 ~m / s ² body is decelerating mass =4 ~kg and F = m a =4 6 4 =6 ~N