A jet plane having a wing span of ( 25 ~m ) is travelling horizontally towards east with a speed of ( 3600 ~km / h ⁻¹ ).If the Earth's magnetic field at the location is ( 4 10⁻⁴ ~T ) and the angle of dip is ( 30^ ), then the potential difference between the ends of the wing is

Step-by-step solution

Given, wing span =25 ~m ; speed of jet plane =3600 kmh ⁻¹ Earth's magnetic field 4 10⁻⁴ ~T ; angle of dip =30^ Now emf, e=B_ v l v (1)B_ v =B =4 10⁻⁴ 30^ =4 10⁻⁴ 1 2 =2 10⁻⁴ ~T v=3600 kmh ⁻¹=3600 5 18 =1000 ~ms ⁻¹l=25 ~m Substituting values in Eq. (1) , we get e=2 10⁻⁴ 1000 25=5 ~V