KCET2017PhysicsMagnetic Properties of Matter
From the following graph of photo current against collector plate potential, for two different intensities of light ( I₁ ) and ( I₂ ), one can conclude
Options
- A( O I₁=I₂ )
- B( I₁>I₂ )
- C( I₁ < I₂ )
- DComparison is not possible.
Correct answer
C. ( I₁ < I₂ )
Step-by-step solution
For a fixed frequency of incident light, photo-current is directly proportional to the intensity. Thus, from graph, photo current for light of Intensity ( I₂ ) is more than for light of intensity ( I₁ ), Therefore, ( I₁ < I₂ )