Two coils have a mutual inductance ( 0.005 H ). The current changes in the first coil according to the equation ( i=i_ m t ) where ( i_ m =10 ~A ) and ( =100 rad s ⁻¹ ). The maximum value of the emf induced in the second coil is

Step-by-step solution

Given, mutual inductance, ( M=0.005 H ; i=i_ t ; i_ m =10 A ; =100 r a d s⁻¹ ) Then emf induced is ( =M d I d t =M d d t (i_ m t )=M i_ m t ) Maximum value of emf is obtained when ( t=1 ). Therefore ( _ =M i_ m =0.005 10 100 =5 ) Thus, maximum value of emf induced in the second coil is ( 5 )