An aircraft with a wingspan of ( 40 ~m ) flies with a speed of ( 1080 ~km ~h ⁻¹ ) in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of the earth's magnetic field ( 1.75 10⁻⁵ ~T ). Then

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An aircraft with a wingspan of ( 40 ~m ) flies with a speed of ( 1080 ~km ~h ⁻¹ ) in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of the earth's magnetic field ( 1.75 10⁻⁵ ~T ). Then the emf developed between the tips of the wings is

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Correct answer: C. ( 0.21 ~V )

Given, length of wing, l=40 ~m ; speed, v=1080 kmh ⁻¹=1080 5 18 ~ms ⁻¹ Earth's magnetic field, B=1.75 10⁻⁵ ~T Then emf E=B l v= (1.75 10⁻⁵ ) 40 1080 5 18 =21000 10⁻⁵=0.21 ~V Therefore, the emf developed between the tips of the wing is 0.21 ~V

An aircraft with a wingspan of ( 40 ~m ) flies with a speed of ( 1080 ~km ~h ⁻¹ ) in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of the earth's magnetic field ( 1.75 10⁻⁵ ~T ). Then the emf developed between the tips of the wings is

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