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KCET2022PhysicsNuclear Physics

Binding energy of a nitrogen nucleus [ ₇¹⁴ ~N ] , given m [ ₇¹⁴ ~N ]=14.00307 u

Options

  1. A85 MeV
  2. B206.5 MeV
  3. C78 MeV
  4. D104.7 MeV

Correct answer

D. 104.7 MeV

Step-by-step solution

Given, mass of mucleus of nitrogen. aligned & m [ ₇ ~N ¹⁴ ]=14.00307 u & Mass of proton, m_r=1.00783 amu & Mass of neutron, m_n=1.0087 amu & Mass defect, m= (7 m_r+7 m_n )-m ( ₇ ~N ¹⁴ ) & =7 1.00783+7 1.00807-14.00307 & =0.11243 amu & aligned Binding energy of nitrogen nucleus aligned & = m 931=0.11243 931 & =104.67=104.7 MeV aligned

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