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KCET2019PhysicsNuclear Physics

The end product of decay of ( ₉₀ T h²³² ) is ( ₈₂ P b²⁰⁸ . ) The number of ( ) and ( ) particles emitted are respectively

Options

  1. A( 6,0 )
  2. B( 3,3 )
  3. C( 4,6 )
  4. D( 6,4 )

Correct answer

D. ( 6,4 )

Step-by-step solution

(D) ( ₉₀ T h²³² ₈₂ P b²⁰⁸ ) Mass number changes by ( 24 ) and hence ( 6 ) a particles are emitted (as ( 1 ) a particle emitted decreased mass number by ( 4 ) ) then proton number should decrease by ( 12 ), but change in proton number is by ( 8 ) and hence ( 4 ) particleshould be emitted so that proton number increased by ( 4 )

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