The ionisation energy of an electron in the ground state of helium atom is 24.6 eV . The energy required to remove both the electron is

Step-by-step solution

Ionisation energy in ground state =24.6 eV Energy required to remove 2^ n electron from He ²⁺ Ionisation energy in ground state =24.6 eV Energy required to remove 2^ n electron from He ²⁺=Z²(13.6) eV =(2)²(13.6)=54.4 eV =Z²(13.6) eV =(2)²(13.6)=54.4 eV So, total energy required =24.6+54.4=79 eV