A and B are the two radioactive elements. The mixtue of these elements show a total activity of 1200 disintergrations/minute. The half-life of A is 1 day and that of B is 2 days. What will be the total activity after 4 days? Given, the initial number of atoms in A and B are equal

Step-by-step solution

We have, A= (N)= 0.693 T_ 1 / 2 (N) Initial number of atoms is A and B are same A₀ 1 T_ 1 / 2 A₀(A) A₀(B) = 48 hr 24 hr =2 Also, A₀(A)+A₀(B)=1200 3 A₀(B)=1200 A₀(B)=400 and A₀(A)=800 So, A(A)= A₀(A) 2⁴ = 800 16 =50 and A(B)= A_ b (B) (2)² = 400 4 =100 Hence, total activity after 4 days is =A₀(A)+A₀(B)=50+100=150 dis / min