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KCET2013PhysicsNuclear Physics

The binding energy/nucleon of deuteron ( ₁ H ² ) and the helium atom ( ₂ He ⁴ ) are 1.1 MeV and 7 MeV respectively. If the two deuteron atoms fuse to form a single helium atom, then the energy released is

Options

  1. A26.9 MeV
  2. B25.8 MeV
  3. C23.6 MeV
  4. D12.9 MeV

Correct answer

C. 23.6 MeV

Step-by-step solution

Given, BE/nucleon for ₁ H ²=1.1 MeV and BE / nucleon for ₂ He ⁴=7 MeV Also, aligned & ₁ H ²+ ₁ H ² ₂ He ⁴+ Q &Q= BE _ P - BE _ R & =4 7-4 1.1=23.6 MeV aligned

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