In a radioactive decay, an element z ^ X emits four -particles, three -particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are

Step-by-step solution

After n _ -decays and n _ -decays, the respective atomic number and mass number of resulting nucleus are given by and Z ^ = Z -2 n _ + n _ = Z -8+3= Z -5 We have, A -4 n _ = A -16