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KCET2008PhysicsNuclear Physics

On bombarding U ²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW , then the rate of fission will be

Options

  1. A5 10²² / s
  2. B5 10¹⁶ / s
  3. C8 10¹⁶ / s
  4. D20 10¹⁶ / s

Correct answer

B. 5 10¹⁶ / s

Step-by-step solution

Energy released on bombarding U ²³⁵ by neutron =200 MeV Power output of atomic reactor =1.6 MW Rate of fission = 1.6 10⁶ 200 10⁶ 1.6 10⁻¹⁹ =5 10¹⁶ / s

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