₉₂ U ²³⁵ undergoes successive disintegrations with the end product of ₈₂ ~Pb ²⁰³ . The number of and particles emitted are

Step-by-step solution

Let number of particles decayed be x and number of particles decayed be y . Then equation for the decay is given by ₉₂ U ²³⁵ x ₂⁴+ y _ -1 ⁰+ Pb ₈₂²⁰³ Equating the mass number on both sides 235=4 x+203 Equating atomic number on both sides 92=2 x - y +82 Solving Eqs. (i) and (ii), we get x=8, y=6 8 particles and 6 particles are emitted in disintegration.