KCET2022PhysicsOscillations
The displacement of a particle executing SHM is given by x=3 [2 t+ 4 ] , where x is in metre and t is in seconds. The amplitude and maximum speed of the particles is
Options
- A3 ~m , 4 ms ⁻¹
- B3 ~m , 6 ms ⁻¹
- C3 ~m , 8 ms ⁻¹
- D3 ~m , 2 ms ⁻¹
Correct answer
B. 3 ~m , 6 ms ⁻¹
Step-by-step solution
Given, displacement equation of particle executing SHM, X=3 [2 t+ 4 ] Comparing with displacement equation of SHM as y=A ( t+ ) , we get Amplitude, A=3 ~m Angular velocity, =2 rad / s Maximum speed, v_ = A=2 3=6 m / s