KCET2016PhysicsOscillations
A particle executing SHM has a maximum speed of ( 0.5 ~ms ⁻¹ ) and maximum acceleration of ( 1.0 ~ms ⁻² ). The angular frequency of oscillation is
Options
- A( 2 rad s ⁻¹ )
- B( 0.5 rad s ⁻¹ )
- C( 2 rad s ⁻¹ )
- D( 0.5 rad s ⁻¹ )
Correct answer
A. ( 2 rad s ⁻¹ )
Step-by-step solution
Given, maximum speed, v_ =0.5 m s⁻¹ ; maximum acceleration, a_ =1.0 m s⁻¹ ; angular frequency, =? Now, we know v_ = A (1) where A is amplitude of oscillation. Also, a_ = ² A (2) Using Eqs. (1) and (2), we get v_ a_ = A ² A v_ a_ = 1 = a_ v_ = 1.0 0.5 =2 rad s⁻¹ Therefore, angular frequency of oscillation is 2 rads ⁻¹