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KCET2013PhysicsOscillations

From a fixed support, two small identical spheres are suspended by means of strings of length 1 ~m each. They are pulled aside as shown and then released. B is the mean position. Then the two spheres collide

Options

  1. Aat B after 0.25 ~s
  2. Bat B after 0.5 ~s
  3. Con the right side of B after some time
  4. Don the right side of B when the strings are inclined at 15^ with B

Correct answer

B. at B after 0.5 ~s

Step-by-step solution

Irrespective of amplitude, both spheres take same time to reach the mean position, i.e., T 4 ~S T=2 l g =2 3.14 1 10 =2 ~s So, they will collide at T 4 = 2 4 =0.5 ~s .

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