A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is With what acceleration should the lift be accelerated upwards in order to reduce its period to T / 2 ? ( is acceleration due to gravity).

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Correct answer: B. 3

Time period of simple pendulum is given by T =2 1 ~g When the lift is moving up with an acceleration , then time period becomes T^ =2 1 g+a Here, T ^ = T 2 T 2 =2 1 ~g + a Dividing Eq. (ii) by Eq. (i), we get a=3 g

A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is With what acceleration should the lift be accelerated upwards in order to reduce its period to T / 2 ? ( is acceleration due to gravity).

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