A luminous point object O is placed at a distance 2 R from the spherical boundary separating two transparent media of refractive indices n₁ and n₂ as shown, where R is the radius of curvature of the spherical surface. If n₁= 4 3 , n₂= 3 2 and R=10 ~cm , the image is obtained at a distance from P equal to

Step-by-step solution

From the given diagram in question, n₁= 4 3 n₂= 3 2 u=-2 R Using refraction formula through convex spherical surface. n₂ v - n₁ = n₂-n₁ R 3 2 v - 4 3(-2 R) = 3 2 - 4 3 R v=-3 R=-3 10 [ R=10 ~cm ]=-30 ~cm Since, v is negative, thus image is obtained at a distance from P equal to 30 cm in the rarer medium.