The diffraction pattern of crystalline solid gave a peak at 2 =60^ . What is the distance (in cm ) between the layers which gave this peak? ( of X-rays is 1.54 Å) ( 30^ =0.5, 60^ =0.866 . ; n=1 )

Step-by-step solution

According to Bragg's law n =2 ~d Given, n = order =1 aligned & = wavelength of x -rays =1.54 ~A ^ & = angle of incidence =30^ & d= interplaner distance aligned (distance between the layers) aligned & n =2 ~d & 1.54 Å=2 d 30^ aligned aligned & 1.54 10⁻⁸ ~cm =2 d 0.5= [1 Å=10⁻⁸ ~cm ] & d =1.54 10⁻⁸ ~cm aligned