The distance between an object and its image produced by a converging lens is 0.72 ~m . The magnification is 2 . What will be the magnification when the object is moved by 0.04 ~m towards the lens?

Step-by-step solution

Given, m=2 and the image formed is real For a real image 1 f = 1 v + 1 u ( u is negative ) array ll Or & 1+ 1 m = u f & 1+ 1 2 = u f & 3 2 = 0.72 f or & f= 0.72 2 3 =0.16 ~m array As the object is moved by 0.04 ~m towards the lens, the new u₁=0.72-0.04=0.68 ~m Again real image is formed So, 1+ 1 m = u₁ f 1 m = 0.04 0.16 m=4