KCET2007PhysicsRay Optics
A vessel of height 2 d is half-filled with a liquid of refractive index 2 and the other half with a liquid of refractive index n (the given liquids are immiscible). Then the apparent depth of the inner surface of the bottom of the vessel (neglecting the thickness of the bottom of the vessel) will be
Options
- An d(n+ 2 )
- Bd(n+ 2 ) n 2
- C2 n d(n+ 2 )
- Dn d d+ 2 n
Correct answer
B. d(n+ 2 ) n 2
Step-by-step solution
Refractive index = Real depth (d) Apparent depth (x x) For 1st liquid, 2 = d x₁ x₁= d 2 Similarly, for 2 nd liquid, n= d x₂ x₂= d n Total apparent depth =x₁+x₂ = d 2 + d n = d(n+ 2 ) n 2