KCET2024PhysicsRotational Motion
A body of mass 1 kg is suspended by a weightless string which passes over a frictionless pulley of mass 2 kg as shown in the figure. The mass is released from a height of 1.6 m from the ground. With what velocity does it strike the ground?
Options
- A16 ~ms ⁻¹
- B8 ~ms ⁻¹
- C4 2 ~ms ⁻¹
- D4 ~ms ⁻¹
Correct answer
D. 4 ~ms ⁻¹
Step-by-step solution
Given, mass of the body, m₁=1 ~kg Mass of pulley, m₂=2 ~kg According to conservation of energy, m₁ g h= 1 2 m₁ v^2+ 1 2 I ^2 aligned = 1 2 ₁ v^2+ & 1 2 m₂ R^2 2 ( v R )^2 & [ I= m₂ R^2 2 and = v R ] aligned m₁ g h= 1 2 m₁ v^2+ 1 4 m₂ v^2 1 10 1.6= 1 2 1 v^2+ 1 4 2 v^2 v^2=4 ~m / s