KCET2022PhysicsRotational Motion
The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 ~s . The angular acceleration of the motor wheel is
Options
- A4 rad / s ^2
- B6 rad / s ^2
- C8 rad / s ^2
- D2 rad / s ^2
Correct answer
A. 4 rad / s ^2
Step-by-step solution
Given, initial angular frequency of wheel, f₀=1200 rpm = 1200 60 rps =20 rps Initial angular velocity, ₀=2 f₀=2 20=40 rad / s Similarly, final angular speed, =2 ( 3120 60 ) rad / s =104 rad / s Time, t=16 ~s If be the angular acceleration of the wheel, then aligned & = ₀+ t & = - ₀ t = 104 -40 16 & = 64 16 =4 rad / s ^2 aligned